50.powx-n

Statement

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Metadata

• Link: Pow(x, n)
• Difficulty: Medium
• Tag: 递归 数学

实现 pow(x, n) ，即计算 x 的 n 次幂函数（即，xn ）。

 

示例 1：

输入：x = 2.00000, n = 10
输出：1024.00000

示例 2：

输入：x = 2.10000, n = 3
输出：9.26100

示例 3：

输入：x = 2.00000, n = -2
输出：0.25000
解释：2-2 = ½2 = ¼ = 0.25

 

提示：

• -100.0 < x < 100.0
• -231 <= n <= 231-1
• -104 <= xn <= 104

Metadata

• Link: Pow(x, n)
• Difficulty: Medium
• Tag: Recursion Math

Implement pow(x, n), which calculates x raised to the power n (i.e., xn).

 

Example 1:

Input: x = 2.00000, n = 10
Output: 1024.00000

Example 2:

Input: x = 2.10000, n = 3
Output: 9.26100

Example 3:

Input: x = 2.00000, n = -2
Output: 0.25000
Explanation: 2-2 = ½2 = ¼ = 0.25

 

Constraints:

• -100.0 < x < 100.0
• -231 <= n <= 231-1
• -104 <= xn <= 104

Solution

Python 3

class Solution:
    def myPow(self, x: float, n: int) -> float:
        return x ** n

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最后更新: January 15, 2023