# 412.fizz-buzz

## Statement

• Difficulty: Easy
• Tag: `数学` `字符串` `模拟`

• `answer[i] == "FizzBuzz"` 如果 `i` 同时是 `3``5` 的倍数。
• `answer[i] == "Fizz"` 如果 `i``3` 的倍数。
• `answer[i] == "Buzz"` 如果 `i``5` 的倍数。
• `answer[i] == i` （以字符串形式）如果上述条件全不满足。

``````输入：n = 3

``````

``````输入：n = 5

``````

``````输入：n = 15

• `1 <= n <= 104`

• Difficulty: Easy
• Tag: `Math` `String` `Simulation`

Given an integer `n`, return a string array `answer` (1-indexed) where:

• `answer[i] == "FizzBuzz"` if `i` is divisible by `3` and `5`.
• `answer[i] == "Fizz"` if `i` is divisible by `3`.
• `answer[i] == "Buzz"` if `i` is divisible by `5`.
• `answer[i] == i` (as a string) if none of the above conditions are true.

Example 1:

``````Input: n = 3
Output: ["1","2","Fizz"]
``````

Example 2:

``````Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]
``````

Example 3:

``````Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
``````

Constraints:

• `1 <= n <= 104`

## Solution

``````from typing import List

class Solution:
def fizzBuzz(self, n: int) -> List[str]:
def run(x: int) -> str:
s = ""

if x % 3 == 0:
s = s + "Fizz"
if x % 5 == 0:
s = s + "Buzz"

if len(s) == 0:
s = str(x)

return s

return list(map(run, range(1, n + 1)))
``````