412.fizz-buzz

Statement

简体中文English

Metadata

Link: Fizz Buzz
Difficulty: Easy
Tag: 数学 字符串 模拟

给你一个整数 n ，找出从 1 到 n 各个整数的 Fizz Buzz 表示，并用字符串数组 answer（下标从 1 开始）返回结果，其中：

answer[i] == "FizzBuzz" 如果 i 同时是 3 和 5 的倍数。
answer[i] == "Fizz" 如果 i 是 3 的倍数。
answer[i] == "Buzz" 如果 i 是 5 的倍数。
answer[i] == i （以字符串形式）如果上述条件全不满足。

示例 1：

输入：n = 3
输出：["1","2","Fizz"]

示例 2：

输入：n = 5
输出：["1","2","Fizz","4","Buzz"]

示例 3：

输入：n = 15
输出：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

提示：

1 <= n <= 10⁴

Metadata

Link: Fizz Buzz
Difficulty: Easy
Tag: Math String Simulation

Given an integer n, return a string array answer (1-indexed) where:

answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
answer[i] == "Fizz" if i is divisible by 3.
answer[i] == "Buzz" if i is divisible by 5.
answer[i] == i (as a string) if none of the above conditions are true.

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Constraints:

1 <= n <= 10⁴

Solution

Python 3

from typing import List


class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        def run(x: int) -> str:
            s = ""

            if x % 3 == 0:
                s = s + "Fizz"
            if x % 5 == 0:
                s = s + "Buzz"

            if len(s) == 0:
                s = str(x)

            return s

        return list(map(run, range(1, n + 1)))

最后更新: October 11, 2023