1150 Travelling Salesman Problem
Statement
Metadata
- 作者: CHEN, Yue
- 单位: 浙江大学
- 代码长度限制: 16 KB
- 时间限制: 250 ms
- 内存限制: 64 MB
The "travelling salesman problem" asks the following question: "Given a list of cities and the distances between each pair of cities, what is the shortest possible route that visits each city and returns to the origin city?" It is an NP-hard problem in combinatorial optimization, important in operations research and theoretical computer science. (Quoted from "https://en.wikipedia.org/wiki/Travelling_salesman_problem".)
In this problem, you are supposed to find, from a given list of cycles, the one that is the closest to the solution of a travelling salesman problem.
Input Specification
Each input file contains one test case. For each case, the first line contains 2 positive integers City1 City2 Dist
, where the cities are numbered from 1 to Dist
is positive and is no more than 100. The next line gives a positive integer
where
Output Specification
For each path, print in a line Path X: TotalDist (Description)
where X
is the index (starting from 1) of that path, TotalDist
its total distance (if this distance does not exist, output NA
instead), and Description
is one of the following:
TS simple cycle
if it is a simple cycle that visits every city;TS cycle
if it is a cycle that visits every city, but not a simple cycle;Not a TS cycle
if it is NOT a cycle that visits every city.
Finally print in a line Shortest Dist(X) = TotalDist
where X
is the index of the cycle that is the closest to the solution of a travelling salesman problem, and TotalDist
is its total distance. It is guaranteed that such a solution is unique.
Sample Input
6 10
6 2 1
3 4 1
1 5 1
2 5 1
3 1 8
4 1 6
1 6 1
6 3 1
1 2 1
4 5 1
7
7 5 1 4 3 6 2 5
7 6 1 3 4 5 2 6
6 5 1 4 3 6 2
9 6 2 1 6 3 4 5 2 6
4 1 2 5 1
7 6 1 2 5 4 3 1
7 6 3 2 5 4 1 6
Sample Output
Path 1: 11 (TS simple cycle)
Path 2: 13 (TS simple cycle)
Path 3: 10 (Not a TS cycle)
Path 4: 8 (TS cycle)
Path 5: 3 (Not a TS cycle)
Path 6: 13 (Not a TS cycle)
Path 7: NA (Not a TS cycle)
Shortest Dist(4) = 8