49.group-anagrams

Statement

简体中文English

Metadata

• Link: 字母异位词分组
• Difficulty: Medium
• Tag: 哈希表 字符串 排序

给你一个字符串数组，请你将 字母异位词 组合在一起。可以按任意顺序返回结果列表。

字母异位词 是由重新排列源单词的字母得到的一个新单词，所有源单词中的字母通常恰好只用一次。

 

示例 1:

输入: strs = ["eat", "tea", "tan", "ate", "nat", "bat"]
输出: [["bat"],["nat","tan"],["ate","eat","tea"]]

示例 2:

输入: strs = [""]
输出: [[""]]

示例 3:

输入: strs = ["a"]
输出: [["a"]]

 

提示：

• 1 <= strs.length <= 104
• 0 <= strs[i].length <= 100
• strs[i] 仅包含小写字母

Metadata

• Link: Group Anagrams
• Difficulty: Medium
• Tag: Hash Table String Sorting

Given an array of strings strs, group the anagrams together. You can return the answer in any order.

An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.

 

Example 1:

Input: strs = ["eat","tea","tan","ate","nat","bat"]
Output: [["bat"],["nat","tan"],["ate","eat","tea"]]

Example 2:

Input: strs = [""]
Output: [[""]]

Example 3:

Input: strs = ["a"]
Output: [["a"]]

 

Constraints:

• 1 <= strs.length <= 104
• 0 <= strs[i].length <= 100
• strs[i] consists of lowercase English letters.

Solution

Python 3

from typing import List


class Solution:
    def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
        m = {}
        for s in strs:
            k = "".join(sorted(s))
            try:
                m[k].append(s)
            except KeyError:
                m[k] = [s]

        return list(m.values())


if __name__ == "__main__":
    s = Solution()

    ans = s.groupAnagrams(["eat", "tea", "tan", "ate", "nat", "bat"])

    print(ans)

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最后更新: October 11, 2023