217.contains-duplicate

Statement

简体中文English

Metadata

• Link: 存在重复元素
• Difficulty: Easy
• Tag: 数组 哈希表 排序

给你一个整数数组 nums 。如果任一值在数组中出现 至少两次 ，返回 true ；如果数组中每个元素互不相同，返回 false 。

 

示例 1：

输入：nums = [1,2,3,1]
输出：true

示例 2：

输入：nums = [1,2,3,4]
输出：false

示例 3：

输入：nums = [1,1,1,3,3,4,3,2,4,2]
输出：true

 

提示：

• 1 <= nums.length <= 105
• -109 <= nums[i] <= 109

Metadata

• Link: Contains Duplicate
• Difficulty: Easy
• Tag: Array Hash Table Sorting

Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct.

 

Example 1:

Input: nums = [1,2,3,1]
Output: true

Example 2:

Input: nums = [1,2,3,4]
Output: false

Example 3:

Input: nums = [1,1,1,3,3,4,3,2,4,2]
Output: true

 

Constraints:

• 1 <= nums.length <= 105
• -109 <= nums[i] <= 109

Solution

Python 3

from typing import List


class Solution:
    def containsDuplicate(self, nums: List[int]) -> bool:
        return len(nums) != len(set(nums))

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最后更新: October 11, 2023